Accounting (secondary) - Scottish Advanced Higher
Q: How do you integrate (sinx)^3 dxy? Updated
First, we must use the special property of trig functions which means that (sinx)n is the same as sinnx. Likewise, (cosx)n=cosnx, (tanx)n=tannx and so on. In this case, we need to start by replacing (sinx)3 with sin3x. Our question has now changed from ?(sinx)3 dx to ?sin3x dx which we can then split up to become ?(sinx)(sin2x)dx. We now need to use integration by substitution and we will start by using u=cosx. By differentiating this, we get to du/dx= -sinx.
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